The Monty Hall paradox
For the first time in the history of this blog, I am going to say something nice about the NY Times. In an article called And Behind Door No. 1, a Fatal Flaw, John Tierney gives the most lucid explanation of the Monty Hall paradox that I have ever read.
Here’s how Monty’s deal works, in the math problem, anyway. (On the real show it was a bit messier.) He shows you three closed doors, with a car behind one and a goat behind each of the others. If you open the one with the car, you win it. You start by picking a door, but before it’s opened Monty will always open another door to reveal a goat. Then he’ll let you open either remaining door.
Suppose you start by picking Door 1, and Monty opens Door 3 to reveal a goat. Now what should you do? Stick with Door 1 or switch to Door 2?
This answer goes against our intuition that, with two unopened doors left, the odds are 50-50 that the car is behind one of them. But when you stick with Door 1, you’ll win only if your original choice was correct, which happens only 1 in 3 times on average. If you switch, you’ll win whenever your original choice was wrong, which happens 2 out of 3 times.
Posted on April 8th, 2008 by pwyll
Filed under: science
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Interesting, but it doesn’t change my opinion of that mullet wrapper.
That is profound, well explained mathematics. Thanks for posting it. If more math teachers could do that, the field’s cup would runneth over.